Both Sides Now, Part 2

 Looking at the same hand as last time, but from the other defender's perspective...

	♠ J 4 ♥ K J 4 ♦ 8 7 6 5 2 ♣ K 7 2
♠ A 10 9 ♥ 10 8 6 5 ♦ Q 3 ♣ Q 9 5 4	N W E S

You	North	Partner	South
		Pass	1 ♠
Pass	1 NT	Pass	2 ♦
Pass	3 ♦	All pass

North's 1NT was forcing one round. You led the ♣ 4. Declarer played low from dummy. Partner played the ♣ J, declarer played the ♣ 6. At trick two, partner led the ♦ 4.

Who has the ♣ A? It seems unlikely that declarer would hold up the ace here, so partner has the ♣ A.

Who has the ♣ 10? Remember the Third Hand Basics: "Third hand high, but no higher than necessary, and keep control over dummy's honor." If partner had the jack and ten, partner would have played the ten, no higher than necessary. So, declarer has the ♣ 10.

If declarer had only two clubs to begin with, you can lead the ♣ Q when you get in, smothering declarer's ten. If declarer and partner both had three clubs, then declarer's ten is protected and the suit is "frozen": whichever side leads the suit gives up a trick. (Work this out on paper if you don't see it.)

The next six tricks proceed:
♦ 4 from partner, ace from declarer, three, deuce.
♦ K from declarer, queen, five, ten from partner.
♥ A from declarer, five, four, three from partner.
♥ 2 from declarer, six, jack from dummy, queen from partner.
♦ J from partner, nine, ♠ 10 from you, six from dummy.
♠ 5 from partner, two, you win with the ace of course.

What now? You know partner has the ♣ A. If declarer has only the ten remaining, you must lead the queen and get two club tricks (declarer is out of trump). If declarer has two clubs remaining, you give up a trick by leading clubs.

How many clubs did declarer start with, two or three?

Remember the auction? Declarer bid 2 ♦ after the forcing notrump. Declarer had three diamonds. If declarer had three clubs and three diamonds, declarer would have bid 2 ♣ rather than 2 ♦. So declarer started with only two clubs. 

So you lead the ♣ Q, smothering declarer's ten, to get two more club tricks.

AND, A BONUS MINUTE...

At trick two, partner led the ♦ 4 from what turned out to be the J-10-4. Why didn't partner make the normal lead of the jack?

1. Partner knows that you know that she has the ace of clubs.
2. Partner knows that you know that she does not have the ten of clubs, because she played the jack rather than the ten.
3. Partner knows that declarer has either the ten or nine of clubs, because you didn't lead the ten from 10-9.
4. Partner knows that if you have Q-10 of clubs, you can lead clubs safely
5. Partner knows that if you have Q-9 of clubs you can't lead clubs unless she had four clubs originally and that you can't determine for sure how many clubs she had.

Aha! Partner realized that you might have a problem in the club suit. She made a non-standard lead, in this case a low trump, to suggest suit-preference low.  It couldn't have been to encourage a heart lead to her unsupported queen without knowing where the heart ace is. So the  ♦ 4  must be encouraging the other low suit, clubs!

Partner did not know where your entry was; if it was in diamonds, you wouldn't have the benefit of those other five tricks to figure out the count in clubs. So she made a trump suit preference play, hoping you could figure out the clue.

-- Ray 

Better Bridge in 5 Minutes. Guaranteed! (or the next one is free)

Both Sides Now, Part 1

Getting the basics right is essential for effective defense. Here's a hand from a recent club pairs game; we will look at it from the perspective of each defender in turn.

	♠ J 4 ♥ K J 4 ♦ 8 7 6 5 2 ♣ K 7 2
	N W E S	♠ Q 7 5 ♥ Q 9 3 ♦ J 10 4 ♣ A J 8 3

Partner	North	You	South
		Pass	1 ♠
Pass	1 NT	Pass	2 ♦
Pass	3 ♦	All pass

North's 1NT call was forcing one round. Partner led the ♣ 4 (standard leads and carding), declarer plays the ♣ 2 from dummy. Your play?

Before playing to the first trick, it's time to do some homework. It certainly looks like a fourth-best club. You can see the two and three, so you know the four is partner's lowest club.

• The ♣ 4 can't be a singleton. If it were, declarer would have a five-card club suit. Yet declarer bid diamonds, on what would then be three diamonds and five clubs. 
• The ♣ 4 can't be a doubleton, because partner would not lead low from a doubleton.
• Could the ♣ 4 be from a three-card holding? Possibly, and there's no way to rule this out. But our play to this trick will be the same either way.

It's still your turn. Your play?

Recall the Third Hand Basics: "Third hand high, but no higher than necessary, and keep control over dummy's honor." Playing the ace here would establish the king in dummy. And if declarer has the guarded queen, that would give her two club tricks! Playing the ace here can never gain a club trick, and usually gives up a trick. So, basic defensive card play mandates playing the jack. 

But wait, don't play the jack just yet... What if partner has both the ♣ 10 and ♣ 9? Then you could just play a very smug ♣ 8. Alas, not possible. If partner had the ten and nine, partner would have led the top-of-sequence ten. From Q-10-9-4, or 10-9-x-4, or 10-9-4, the standard lead is the ten. We can rule out those possible holdings for partner.

So, the ♣ J it must be. The jack holds the trick, declarer plays the ♣ 6. Partner must have the club queen, as you hoped. Now what?

Assuming the ♣ 4 was fourth-best, you now know the layout of the club suit almost exactly. Declarer started with two clubs, one of which is the ten or nine. Recall that partner's lead denied having both the ten and nine. If partner has four clubs without the ten or nine, then declarer would have started with ten-nine doubleton and would have played one of those cards. Therefore, partner started with Q-10-5-4 or Q-9-5-4 and declarer has the other high spot card.

If you lead any club now, you will set up dummy's king. (You could try leading the ace just in case the king decides to commit suicide, but that never seems to work at my table.) 

Notice that if partner gets in and leads the ♣ Q, that will trap ("smother") declarer's remaining high spot card. But partner doesn't know that declarer started with a doubleton. Is there a way to tell partner that you had four clubs instead of three? Unfortunately no, not directly. But you can give partner a hint...

You have to lead something other than a club. Partner must have some other high cards outside of clubs, because declarer declined the game invitation and thus denied a maximum hand.

• If declarer has ace-king of spades, leading a spade trashes your ♠ Q.
• If declarer has the ace of hearts, leading a heart trashes your ♥ Q.

Exiting with a diamond seems best to me; maybe partner's high honor is in diamonds. At least a diamond lead is unlikely to give up a diamond trick. The standard lead from J-10-4 is the jack, but I would lead the ♦ 4 in this case.

Stay tuned for Part 2...

-- Ray
Better Bridge in 5 Minutes. Guaranteed! (or the next one is free)