Continuing
with our monster six-five hand… matchpoints, not vulnerable.
♠ A K J x x ♥ x x ♦ -- ♣ A K Q J 10 x
You
|
Partner
|
1 ♣
2 ♠
3 ♠
4 ♠
?
|
1 ♥
2 NT
4 ♦
5 ♥
|
You showed a strong hand with six-five
distribution. Partner perked up by bidding 4 ♦, a cue-bid showing the ace of diamonds and
implying support for spades. The diamond ace doesn’t do much for your hand,
though. Your 4 ♠ call is
ambiguous as either a sign-off or a cue-bid for the ace of spades; however
partner interprets it is fine with you. Partner forges ahead, showing the heart ace with her 5 ♥ call.
Cool, we have
all the aces! Partner has implied three-card spade support, and has at least
two clubs for her earlier NT bid. You can count six club tricks and two red
aces. If partner holds the Q♠, you can almost
always rely on five spade tricks. If partner doesn’t have the Q♠, you still have a reasonable chance for four
spade tricks, and even five spade tricks about a third of the time (a 3-2 split
with the missing queen on your right). So, it’s your call: five, six or seven?
Clubs, spades, or something else?
ANSWER: Bid 7 ♣, though 7 ♠ is a close second choice. At this point in
the auction I don’t know of a way to ask partner about the Q♠; you’ll have to just make up your mind and place
the contract. If she has the queen (at least a 3/8 chance) it should be easy to
make 7. If she doesn’t have the queen (at worst a 5/8 chance) you still have at
least a 50-50 chance with a finesse.
THE PRINCIPLE: At matchpoints, bid a small slam (six of
something) if it has at least a 50-50 chance of making. For a grand slam, you want
at least a 67% chance. At IMP scoring (duplicate teams), it’s usually best
to set your standards a little higher; at IMPs you avoid bidding grand slams
unless you can count 13 tricks.
WHY NOT 7 ♠? My opinion goes this way: Partner denied a four-card spade holding, and promised at least two clubs. She might have three or even four clubs,
giving you a nine- or ten-card club suit. The potentially better fit in clubs could help protect against a bad spade split by ruffing spade losers in dummy.
Also, if you have 9 or 10 clubs between the two hands, there is an increasing chance (5% or 11%) that your right hand opponent is void in clubs; in that case, she’ll make
a Lightner double to request a club lead for a ruff, down one
right out of the chute. Though you could have a similar problem in the spade
suit with clubs as trump, the chances of the 5-0 wrong-side spade split is only
about 2%.
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